9x^2-36x+33=0

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Solution for 9x^2-36x+33=0 equation:



9x^2-36x+33=0
a = 9; b = -36; c = +33;
Δ = b2-4ac
Δ = -362-4·9·33
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{3}}{2*9}=\frac{36-6\sqrt{3}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{3}}{2*9}=\frac{36+6\sqrt{3}}{18} $

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